Today prof Mason showd us how to determine the power that delivered by AC source.
For this picture, Professor Mason used the same voltage for AC power and DC power. The bulb powered by AC source is dimmer than the bulb powered by DC source.
When professor Mason turns the voltage for AC to about 1.4 times of the DC power, they seems the same bright. The Peak voltage of AC source is about 1.4 which is roughly square root of 2 times the voltage of DC source,
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